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...this is the basic plan of Giza...
3 main pyramids: G1, G2 and G3
...in purple, orange and green, respectively...
describing a rectangle with curious proportions
east to west = 1000 times the square root of 2
north to south = 1000 times the square root of 3
the hypotenuse = 1000 times the square root of 5
this is the first thing you should see
...before doing... anything, really...


...as for... where to begin... to model the pyramids...
below image: Quickbird satellite photo of the Giza Plateau
GPMP Giza Plateau Mapping Project (above) large (995x1000) giant (1991x2000)
Siloam 180 rotated diagram of Giza (below) large (1146x1218) giant (2291x2436)



(click pic for hi-rez)


...yeah, right...
i went to Legon


from: http://goodfelloweb.com/giza/jlpamp.html
...These details suggest that there was some factor, more important than considerations of architectural setting or ease of construction, which determined where the three Pyramids were positioned. Another indication is given by the very regular arrangement of these Pyramids on the plateau (fig. 1). Firstly, the square bases are accurately aligned with respect to the four cardinal points, the Great and Second Pyramids having the same orientation within two minutes of arc. Secondly, the three Pyramids lie along a diagonal line from the northeast towards the southwest, so that the sides of the bases, and the distances that separate them, form consecutive dimensions along two axes, from north to south and from east to west. In this we have the basis of a coherent dimensional scheme, suggesting that the placing of the three Pyramids might be explained by the existence of an underlying ground plan. How might this be tested?
The Great Pyramid possesses the "pi proportion", whereby the height of 280 cubits is to the perimeter of the base of 1760 cubits, as the radius of a circle is to its circumference (for pi = 22/7). The sides of the base thus measure 440 cubits, with an adjustment in three sides evidently to give the more accurate mean side 280 x pi/2 = 439.8...cubits.
The dimensions relating the Second Pyramid to the Great Pyramid follow a very simple scheme which was, however, slightly modified to take account of the placing of the Third Pyramid. In this scheme (fig. 2), the north side of the Second Pyramid is set on a line just 250 cubits south from the south side of the Great Pyramid; and the south side of the Second Pyramid, on a line 1, 1/2 x 440 = 660 cubits south from the south side of the Great Pyramid, and hence 2, 1/2 x 440 = 1100 cubits south from the north side of the Pyramid.
Similarly along the east-west axis of the plan, the west side of the Second Pyramid is placed 2, 1/2 x 250 = 625 cubits west from the west side of the Great Pyramid. In practice, for reasons given below, one cubit was subtracted from the dimension 625 and added to the dimension 1100 (fig. 3), and so the sides of base of the Second Pyramid measure 1101 - 250 - 440 = 411 cubits. The position of the Third Pyramid defines the overall dimensions of the plan, which are 1417.5 or about 1000 root 2 cubits from east to west, and 1732 or exactly 1000 root 3 cubits from north to south. The theoretical dimensions can be obtained by taking firstly, a square of side1000 with diagonals of 1000 root 2; and secondly, a rectangle measuring 1000 by 1000 root 2 with diagonals of 1000 root 3; but the actual dimensions derive from the placing of a scheme of the "circle squared" for the Third Pyramid, relative to the Second Pyramid.
at this point (so, i didn't do this right away)
i'm unclear on where, specifically, to place G3
This scheme (fig. 4) is based on a square of side 500 cubits, which is placed diagonally to the axes of the plan and enclosed within a circle, radius 250 root 2 or 353.5 cubits. The circumference of the circle, 2220 cubits (for pi = 3.14), is now made the perimeter of a second square, centered on the first, with its sides of 555 placed axial to the plan. Along these sides, the points of intersection with the first square mark off the side of base of the Third Pyramid, 555 - 353.5 = 201.5 cubits.

As shown in figure 4, the radius of the circle 353.5 is made the axial distance west from the west side of the Second Pyramid to the west side of the Third Pyramid. This distance is exactly one-quarter of the nominal overall dimension on the same axis, 1000 root 2 or 1414 cubits, which became, however, 353.5 + 624 + 440 = 1417.5 cubits. On the north-south axis, the line of the south side of the Second Pyramid being tangent to the circle, it is 353.5 + 555/2 root 2 = 631 cubits north from the south side of the Third Pyramid, so that the overall dimension became 631 + 1101 = 1732 or exactly 1000 root 3 cubits. Thus the adjustment of one cubit between the dimensions 624 and 1101, made both overall dimensions more accurate.

following the instructions as spelled out above
the simple method: measuring
1417.5 west from G1ne corner
and 1732 south, to find G3se
...but i want my coordinates
...based on the center of G1
so, minus 220, for half of G1
(being 440 cubits each side)
1417.5 - 220 = 1197.5
1732.0 - 220 = 1512.0
so my G3se should be
( -1197.50 , -1512.00 )
...now, G3 center point:
which, at 201.5 per side
and half of that is 100.75
subtract that from those...
1197.50 - 100.75 = 1096.75
1512.00 - 100.75 = 1411.25
coords for G3 center
( -1096.75 , -1411.25 )
but, just to make sure, double check
i want to do the rotator method, too
following the instructions up to figure 3:
. . . 624 + 440 = 1064 ... - 220 = 844 (west)
411 + 250 + 440 = 1101 ... - 220 = 881 (south)
(as, again, i'm being relevant to G1 center)
so, SW corner of G2 should be ( -844 , -881 )
south of that... 353.5 radius
for the center of the rotator
881 + 353.5 = 1234.5 (south)
...but... east-west... of... where ?
the circle is 353.5 radius, diam 707
the circle's... internal square is 500
the second square has sides of 555
...flush to the west edge of the plan
so, half of that (555/2) = 277.5
and... 1417.5 - 277.5 = 1140
then ... 1140 - 220 = 920

so my G3 rotator should be
centered at (-920, -1234.5)
oh, notice that... ( 1.2.3.4.5 )
and the other is 80 from 1000
1 x 2 x 3 x 4 x 5 = 15
1 + 2 + 3 + 4 + 5 = 120

120 / 15 = 8
15 / 120 = 0.125
defining an octagon

+15 x 120 = 1800 = 90 x 20
in the image above, i noticed an error
...the program has correctly computed
the dimensions of the group as 707.11
(rounding to the nearest hundredth unit)
(and take a casual notice of the 7 and 11)
angle: root 2 (1.414...) x 250 = 353.553...
double that for the diamond = 707.1067...
close enough, maybe... certainly, perhaps
but i want to get as accurate as possible
for some of these wide scale correlations
...spanning 3000 cubits, a degree is alot
so, now what i'm going to do is...
put dots as markers in the centers
of all 4 of these green corner boxes
(one of which gets to be G3's plane)
...the diamond is... 500 per side...
so, that's... 250 units, from center
again, it's (-920, -1234.5).........
so, north = (-920 , -984.5): (z+250)
and south = (-920, -1484.5): (z-250)
and east = (-670, -1234.5): (x+250)
and west = (-1170, -1234.5): (x-250)
...and giving them each
55 unit (cubit) diameters
they just touch the edge
of the upright 555 square
which is how the numbers
are working proportionally
the vertical line (yellow)
has been made flush with
G2's west edge (above right)
and given a 2 cubit width
the light yellow angle is GPH
the grand plan hypotenuse
it runs from G1nw to G3sw
...at an angle of: 29.44
(60.56 counterclockwise)
a distance of 1989 cubits
...but notice how it also
intersects the SE corner
of the square above it
and in the lower image:
same 4 blue marker dots
grouped and rotated 45
lower left dot for G3
(-1096.78, -1411.28)
..and comparing to..
coords for G3 center
(-1096.75, -1411.25)
a difference of 0.03 cubits
times root 2 for the angle
0.042426406871192851...
which is probably more than
the given margins of errors
for ground measurements
so i'll just leave G3 in as is
(keeping that 0.03 in mind)
and resizing the dot
to a single unit (cubit)
(max zoom wireframe)
...to show how close...
a cubit is 20.62 inches
or 52.375 centimeters
times that pesky 0.03
...1.57125 cm...
...15.7125 mm...
...0.6186 inches
...which is... approximately "phi"
that's just... completely strange
phi equals half root 5 minus 0.5
0.6180339887498948482045...
that phi divided by 0.03 =
20.6011329583298282734...


below left
G3 center
again, these coordinates
are relevant to G1 center
so, dividing them in half
i get (-548.39, -705.64)
this would be the
midpoint between
the center points
of G1 and G3
duplicating and converting
this same object to a cube
...1787.3 cubits at 37.85
it's as close as i can get
for the line
connecting
those 2
points
below right
G1 center


from: http://goodfelloweb.com/giza/jlpamp.html
The Great Pyramid possesses the "pi proportion", whereby the height of 280 cubits is to the perimeter of the base of 1760 cubits, as the radius of a circle is to its circumference (for pi = 22/7). The sides of the base thus measure 440 cubits, with an adjustment in three sides evidently to give the more accurate mean side 280 x pi/2 = 439.8...cubits.
here, i've added a sphere (S1) superimposed over G1
(each with the same height or radius of 280 cubits)
(click pic for hi-rez)
...and the cage texture... is just...
something i threw on there, but...
...in googling, for measurements...
...i found something interesting...
from: http://www.earthmatrix.com/extract76.html
...the calculated latitude of the Great Pyramid center is then 29 degrees 58 Min. and 51.045 Seconds with one simple assumption. That being that the lightspeed latitude is exactly 120 cubits south of the SE corner of the Great Pyramid. (6/5 = 1.2 is a very important number to Egyptians and a musical harmony).
...not really... fully understanding...
...much more than the... general jist...
the reasoning behind the LL line involves
alignments to other sites around the world
...and, i've read some stuff on this before...
dudeman.net/siriusly/0/sup/sacgeom.html
dudeman.net/siriusly/0/sup/geogeom.html
while it sounds too freaky to be true, look:
follow the source links, on those pages...
...you really just can't make this stuff up...
besides Giza: Angkor Wat, the Nazca lines,
Easter Island, Machu Picchu, Tiahuanaco, Ur,
Ollantaytambo, Aneitum Island, Yonaguni...
...that's just where these places are, so...
yeah, sci-fi name or not, the line goes in
...besides... it's 120 cubits south of G1s
and, given the nature of the geometry, just so far
...i have no reason to assume that the speed of light
is not encoded somehow within the overall geometry
(even accidentally, such completely cosmic numbers)
of this pyramid complex, or any other ancient site...
in fact, now that someone's mentioned it...
it seems much more reasonable to assume
...that there are many universal constants
...encoded in the fractal balanced harmony
...of whatever proportions, yet to discover
(click pic for hi-rez)
and starting with
...the obvious...
above image: the east-west "Lightspeed Latitude" line (LL) is put in (white)
120 cubits south of the south edge of G1 (and 340 cubits south of G1 center)
...and a 120 cubit square (green) is placed between south edge of G1 and LL
then a 60x120 cubit half square (red) is placed over that, between S1 and LL
...which is thus bisected by the edge of the circumference of the sphere S1
(S1's radius of 280, minus G1's 220 side, leaves 60 cubits at exact center)
which is geometrically implied by the dimensions of G1 (1st quote above)
...thus, creating two half squares (red, green) of 120x60 cubits each...
in the 3D model, the object for LL is a box 2 cubits high and 2 cubits thick
as are the other lines, throughout, which measure the site's proportions
...and rephrasing for clarity
...S1, as the sphere of G1...
cuts that square, right in half
(at the exact center line of G1)
its radius is 140, diameter 280
(as the height of G1 being 280)
compared to a side of G1 at 440
half that distance is an even 220
(which is: 20 x 11 ...or... 10 x 22)
(for 22/7 ...for an approximate pi)
which leaves 60: 220 + 60 = 280
...and 440 - 280 = 160 = 4 x 40
so within the proportions of G1
as side length relating to height
are 2 approaches to 120 cubits:
... 40 x 3 ...and... 60 x 2 ...
which leaves the other obvious
60 + 40 + 20 or: (2+3+4+3) x 10
60 + 40 = 100 ...that's the scale
at which G1 is representing pi


the below image is from a later page
the LL line is made 120 cubits wide
and interesting things with spheres
(click pic for hi-rez)












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