Giza
 G1-G2 Square

 ```the 2 main pyramids, G1 and G2 are offset, slightly, from 45° by an odd rectangle measuring: ...213 cubits by 250 cubits... ``` ```...a proportion of: 50 to 42.6 or one to 1.173708920187793... or opposite reciprocated (1/x) = one to 0.852 even... hmm,,, 0.852 / 213 = 0.004 exactly... ...4 thousandths of a cubit... now, that is something special ```
 ```...blue shaded area hereby dubbed bG1G2 for the box between the SW corner of G1 and NE corner of G2 measures 250 cubits ..north to south... n an odd 213 cubits ...east to west.... .... 250 x 213 .... 53,250 cubit square ```
 ```LL crosses right through it, almost halfway... dividing it into two rectangles of 120 and 130 ```
 ``` 120 x 213 = 25,560 square cubits 130 x 213 = 27,690 square cubits total area = 53,250 square cubits half areas = 12,780 and 13,845 50,000 + 3,250 = 52,000 + 1,250 50K + (13x250) = (13x4K) + (5x250) 250 = (25x10) = (5x50) = (50x10)/2 250 = (5x5x5)x2 = 5 cubed, times 2 13 = (5x2)+3; (7 from 20) and the 5th prime number ...not counting 1 and 2 anyways, 5 and 2 are 7 stagger 6 for 2 and 3 ```
 ```...what geometry might we derive is implied, here ? for example... the center triangle's height is 5... but what are the other measurements... angles etc ? ...i'm reminded of a pentagram... but it's squashed ...or, maybe a hexagon... close, but not exactly... ``` ```entire section: a2+b2=c2 red and yellow angles (213x213) + (250+250) 45,369 + 62,500 = 107,869 c = 328.43416387458841... ```
 ```north section: a2+b2=c2 blue and green angles (213x213) + (120x120) 45,369 + 14,400 = 59,769 c = 244.4769927825520... ``` ```south section: a2+b2=c2 violet and orange angles (213x213) + (130x130) 45,369 + 16,900 = 62,269 c = 249.5375723212839... ```
 ```got this pic from wiki... n modified it a lil http://en.wikipedia.org/wiki/Square_root_of_5 ```
 ```the red square above = 1 by 1 the angle for the half square is half root 5... or 1.118... ``` ```now make a rectangle with that for a side and 1 for the other: ```
 ```Don Barone: 213 divided by 250 = 0.852 sine 0.852 = 58.43 degrees reciprocal (90-58.43) = 31.57 ...sine 31.57 is 0.5235418... nothing special... HOWEVER... close to golden ratio, phi is tan of 31.57 = 0.61448566... and the angle we need to get exactly phi... 0.618033988... = 31.717474380370653213260... ...so, taking this from 90... = 58.282525619629346786739... and sine of this, gives us... = 0.850650808637316884920... and, multiplying this by 250: = 212.66270215932922123010... 0.33 cubits... about 7 inches ...but the 250 IS NOT EXACT ! it would appear that Phi seems to be hidden here in this offset for the distance IS NOT EXACTLY 250 it could be that it works out EXACTLY and that the angles of this rectangle are EXACTLY 58.2825... and 31.71747.. A GOLDEN RECTANGLE !!!!!!! Very, very interesting !!! ```
 ```the square root of 5 is: 2.236... thus, half of root 5 is: 1.118... ...so, the ratio is 1 to 1.118... plus one half: (1/2) (0.5) is phi the golden ratio: one to 1.618... or, reciprocated: one to 0.618... see how that works... this number ```
 ```but... the ratio of 250:213 is small side to 1.173..... or large side to 0.852 even ```
 ```0.852 / 213 = 0.004 times 1000 = 4 250 / 1000 = 0.25 ```
 ```these ratios are found everywhere in nature... seashells, flower petals, faces and fingers... but in practice, curves don't change abruptly: it's more of a gradually adjusting inclination. so, the average arc for each section is correct, and the sides touch, but there's no sudden shift so our alignments will be a bit off now and then but it's representative... reflective, of nature ```
 ```expressed simply in the Fibonacci sequence... ...adding the last 2 numbers to get the next... 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144 ... etc... 3:5, 5:8, 8:13, 13:21, 21:34, 34:55, 55:89 89:144 (the higher up you go, the more accurate you get) ...and... notice the little pyramid triangles... ```
 ```...basically... the proportions of the small section to large section, equals large section to total... and so on... ```
 ```the box between G1 and G2: is comparing the distances ... 250 and 213 cubits ... ```
 ```...so, allowing for... ...a margin of error... ...of about 4 cubits... ...i set up two arcs... with radii of 250 cubits ... 1 at the G1sw corner and 1 at the G2ne corner ```
 ```they intersect 2.75 south (11/4 of a cubit, exactly) of the G1 south line (-220) ...where they also intersect... that big yellow line from before ...spanning from G1nw to G1sw... GPH... for Grand Plan Hypotenuse ```
 ```...or... put more formally... aG1sw-250 and... aG2ne-250 cross at "GPH" ...Grand Plan Hypotenuse or G1nw-G3sw... the line connecting G1nw and G3sw ...each of the 3 sharing the same intersect point ```
 ```the above image is a tight zoom in on the far upper left corner of the below image: ``` ```again, this is the box between G1sw and G2ne with the 250 arcs put in, and various angles ```
 ```...above image: same area (bG1sw-G2ne) with a hexagon: (216.52ew x 250.00ns) and 2 pentagons: (212.92ew x 202.61ns) ...superimposed... half transparent... ``` ```...below image: same scene, wider angle with several more points and angles etc ...note the chords and curious crossings and a very close to equilateral triangle ```
 ```root 2 graph (left) side value, vertical angle value, horizontal one pixel = 0.5 units ```
 (click pic for hi-rez)
 ```if there were a little pyramid ...in the center of that box... side 106.0660... = angle 150 (even) side 120 (even) = angle 169.7056... side 150 (even) = angle 212.1320... side 160 (even) = angle 226.2741... side 170 (even) = angle 240.4163... side 180 (even) = angle 254.5584... side 181.0193.. = angle 256 (even) side 190 (even) = angle 268.7005... side 200 (even) = angle 282.8427... side 203.6467.. = angle 288 (even) side 205.0609.. = angle 290 (even) side 210 (even) = angle 296.9848... side 212.132... = angle 300 (even) side 215 (even) = angle 304.0559... side 219.2031.. = angle 310 (even) side 220 (even) = angle 311.1269... side 232.213... = angle 328.4 given ```
 ```interlocking circles reminds me of vesica ```
 ```and, of course, these 250 cubit arcs ...don't align to vesica... for that, their shared radius would have to be: ...the distance from their centers... the hypotenuse of the rectangle bG1G2 ```
 ```the idea behind a vesica is that: 2 circles share the same radius, in common ```
 ```remembering from before... that distance is 328.43... ``` ```half of that is 164.215... 100 + 64 = (60+40) + (8x8) = (2.3.5.2) plus (2.2.2.5) plus... 2 to the 6th power ```
 ```...but see how close, the... ...center vertical of the... rough overlay vesica (below) (same 250 cubit radius arc) conforms to a side of G1... (checking the math on that) ...radius times... root 3... /3 x 250 = 433.0127018922... just less than 7 cubits less ```
 ```it might strangely work for G2 also, somehow... 433 is 3 times over 400 what G2 side is, at 411 (11x3=33); and then a 7 ...that brings us to 40 G1 down to 400, with G2 ```
 ```i also like that equaliateral triangle (sides same as the radius, 250 cubits) marking a chord on aG1sw, intersecting GPH (grand plan hypotenuse): G1nw-G3sw ``` ```and, here, giving aG1sw a vesica clone to the west: they too intersect at GPH (green-yellow diagonal) ``` ```and a couple other points of interest that pop right out (circled, below)... ```
 ```...the lower left circle... was zoomed in on earlier... aG1sw-aG2ne (-470, -222.75) ``` ```the image below is a zoom of the upper circle point ...in the image above... ``` ```...and the lower right circle ...south G1 center (30, -220) is discussed on the next page ```
 ```it seems to me, that 29.44° if made, to be an even 30° taking into consideration ...that the base of G1... is significantly lower... than the rest of the plan... ...like... 30 cubits, or so... i don't recall exactly, and it's information i don't have handy... (just putting the idea out there) keep it in mind for spheres later ```
 (click pic for hi-rez)

 Giza
 G1-G2 Square
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